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1. Every sample of size 6 has equal chance (randomly choose 6 students out of 30). Answer followingquestions:(a) How many possible samples?We have a total of 30 students and want a sample of 6, therefore we must calculate how manycombinations of 6 we can make out of 30, 306 = 593,775 possible samples.(b) p(s) = ?The probability of selecting a specific sample is 1/593,775 = 0.0000016841() = {153,7750 6 (c) ns = ?The size of the sample is = 6(d) Number of sample containing unit k?If we include unit k in the sample, we have 5 more spots to fill from the 29 students left. That is29C5=118,755.(e) First order inclusion probabilities?The probability that unit k is included in the sample, ( ), denoted as , is =6 = 1,2, 3030 =1 = 1,2, 305(f) Second order inclusion probabilities?The probability that units k and l are included in the sample, (, ), denoted as , is =6(6 1) = 1,2, 3030(30 1) =30 = 1,2, 30870 =1 = 1,2, 30292. If the design (. ) has a fixed sample size n, then + .We know that for simple size n from a population N, we ...
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